And how do you figure that? The Intel 80386DX did NOT have any 80 bit instructions at all, the built in math co-processor came with i486. The only instructions on a 80386DX system that would be 80 bit would be to add a 80387 math co-processor.
But you obviously don’t count by a few extended instructions, but by the architecture of the CPU as a whole. And in that regard, the Databus is a very significant part, that directly influence the speed and number of clocks of almost everything the CPU does.
The Intel 80386DX did NOT have any 80 bit instructions at all, the built in math co-processor came with i486.
You’re right, I misremembered.
And in that regard, the Databus is a very significant part, that directly influence the speed and number of clocks of almost everything the CPU does.
For those old processors, yes, that’s why the 6502 was 8-bit, for modern processors, though? You don’t even see it listed on spec sheets. Instead, for the external stuff, you see number of memory controllers and PCIe lanes, while everything internal gets mushed up in IPC. “It’s wide enough to not stall the pipeline what more do you want” kind of attitude.
Go look at anything post-2000: 64 bit means that pointers take up 64 bits. 32 bits means that pointers take up 32 bits. 8-bit and 16-bit are completely relegated to microcontrollers, I think keeping the data bus terminology, and soonish they’re going to be gone because everything at that scale will be RISC-V, where “RV32I” means… pointers. So does “RV64I” and “RV128I”. RV16E was proposed as an April Fool’s joke and it’s not completely out of the question that it’ll happen. In any case there won’t be RV8 because CPUs with an 8-bit address bus are pointlessly small, and “the number refers to pointer width” is the terminology of <currentyear>. An RV16 CPU might have a 16 bit data bus, it might have an 8 bit data bus, heck it might have a 256bit data bus because it’s actually a DSP and has vector instructions. Sounds like a rare beast but not entirely nonsensical.
Doesn’t mean it’s any less important, it’s just not a good marketing measure,because average people wouldn’t understand it anyway, and it wouldn’t be correct to measure by the Databus alone.
As I stated it’s MORE complex today, not less, as the downvoters of my posts seem to refuse to acknowledge. The first Pentium had a 64 bit Databus for a 32 bit CPU. Exactly because data transfer is extremely important. The first Arm CPU was designed around as fast RAM access/management as possible, and it beat the 386 by several factors, with a tenth the transistors.
Go look at anything post-2000: 64 bit means that pointers take up 64 bits. 32 bits means that pointers take up 32 bits.
Although true, this is a very simplistic way to view it, and not relevant to the actual overall bitwith of the CPU, as I’ve tried to demonstrate, but people apparently refuse to acknowledge.
But bit width of the Databus is very important, and it was debated heavily weather it was even legal to market the M68008 Sinclair QL as a 32 bit computer, because it only had an 8 bit databus.
But as I stated other factors are equally important, and the decoder is way more important than the core instruction set, and modern higher end decoders operate at 256 bit or more, allowing them to decode multiple ( 4 ) instructions per cycle, again allowing each core to execute multiple instructions per clock, in 2 threads. Without that capability, each core would only be about a third as fast.
To claim that the instruction set determines bit wdth is simplistic, and also you yourself argued against it, because that would mean an i486 would be an 80 bit CPU. And obviously todays CPU’s would be 512 bit, because they have 512 bit instructions.
Calling it 64 bit is exclusively meant to distinguish newer CPU’s from older 32 bit CPUS, and we’ve done that since the 90’s, claiming that new CPU architectures haven’t increased in bit width for 30 years is simply naive and false, because they have in many more significant ways than the base instruction set.
Still I acknowledge that an AARCH64 or AMD64 or i64 CPU are generally called 64 bit, it was never the point to refute that. Only that it’s a gross simplification of what modern CPU’s have become, and that it’s not technically correct.
Let me finish with a question:
With a multi-core CPU where each core is let’s just say 64 bit, how many bits is the whole CPU package? Which is what we call the “CPU” today, when saying CPU we are not generally talking about the individual cores, because then it would have to be plural.
As I stated it’s MORE complex today, not less, as the downvoters of my posts seem to refuse to acknowledge.
The reason you’re getting downvoted is because you’re saying that “64-bit CPU” means something different than is universally acknowledged that it means. It means pointer width.
Yes, other numbers are important. Yes, other numbers can be listed in places. No, it’s not what people mean when they say “X-bit CPU”.
claiming that new CPU architectures haven’t increased in bit width for 30 years is simply naive and false, because they have in many more significant ways than the base instruction set.
RV128 exists. It refers to pointer width. Crays existed, by your account they were gazillion-bit machines because they had quite chunky vector lengths. Your Ryzen does not have a larger “databus” than a Cray1 which had 4096 bit (you read that right) vector registers. They were never called 4096 bit machines, they Cray1 has a 64-bit architecture because that’s the pointer width.
Yes, the terminology differs when it comes to 8 vs. 16-bit microcontrollers. But just because data bus is that important there (and 8-bit pointers don’t make any practical sense) doesn’t mean that anyone is calling a Cray a 4096 bit architecture. You might call them 4096 bit vector machines, and you’re free to call anything with AVX2 a 256-bit SIMD machine (though you might actually be looking at 2x 128-bit ALUs), but neither makes them 64-bit architectures. Why? Because language is meant for communication and you don’t get to have your own private definition of terms: Unless otherwise specified, the number stated is the number of bits in a pointer.
64-bit integers, memory addresses, or other data units[a] are those that are 64 bits wide. Also, 64-bit central processing units (CPU) and arithmetic logic units (ALU) are those that are based on processor registers, address buses, or data buses of that size.
It also states Address bus, but as I mentioned before, that doesn’t exist. So it boils down to instruction set as a whole requiring 64 bit processor registers and Databus.
Obviously 64 bits means registers are 64 bit, the addresses are therefore also 64 bit, otherwise it would require type casting every time you need to make calculations on them. But it’s the ability to handle 64 bit registers in general that counts, not the address registers. which is merely a byproduct.
You were arguing the definition of “X-bit CPU”. We’re not talking about “X-bit ALU”. It’s also not up to contention that “A 64-bit integer is 64 bit wide”. So, to the statement:
Also, 64-bit central processing units (CPU) and arithmetic logic units (ALU) are those that are based on processor registers, address buses, or data buses of that size.
This does not say which of “processor register, address buses, or data buses” applies to CPU and which to ALU.
Obviously 64 bits means registers are 64 bit, the addresses are therefore also 64 bit,
Having 64 bit registers doesn’t necessitate that you have 64 bit addresses. It’s common, incredibly common, for the integer registers to match the pointer width but there’s no hard requirement in theory or practice. It’s about as arbitrary a rule as “Instruction length must be wider than the register size”, so that immediate constants fit into the instruction stream, makes sense doesn’t it… and then along come RISC architectures and split load immediate instructions into two.
otherwise it would require type casting every time you need to make calculations on them
I’m sorry are we somehow assuming floating-point pointers, now, of course you need to convert there. “casting” is a specific thing you do in C which may or may not involve conversion of actual data. Processors don’t speak C. Processors don’t have a type system.
In computer science, type conversion,[1][2] type casting,[1][3] type coercion,[3] and type juggling[4][5] are different ways of changing an expression from one data type to another.
You don’t even have a clue, you are just talking trash.
In assembly you don’t generally talk about pointers, but address modes. Like register, immediate or memory (indirect).
Have you ever actually been programming any serious assembly? Because you sure don’t sound like it.
Where did you get that from? Because that’s false, please show me dokumentation for that.
64 bit always meant the ability to handle 64 bit wide instructions, and because the architecture is 64 bit, the pointers INTERNALLY are 64 bit, but effectively they are only for instance 40 bit when accessing data.
Your claim about pointer width simply doesn’t make any sense.
That the CPU should be called by a single aspect they can’t actually handle!!! That’s moronic.
And how do you figure that? The Intel 80386DX did NOT have any 80 bit instructions at all, the built in math co-processor came with i486. The only instructions on a 80386DX system that would be 80 bit would be to add a 80387 math co-processor.
But you obviously don’t count by a few extended instructions, but by the architecture of the CPU as a whole. And in that regard, the Databus is a very significant part, that directly influence the speed and number of clocks of almost everything the CPU does.
You’re right, I misremembered.
For those old processors, yes, that’s why the 6502 was 8-bit, for modern processors, though? You don’t even see it listed on spec sheets. Instead, for the external stuff, you see number of memory controllers and PCIe lanes, while everything internal gets mushed up in IPC. “It’s wide enough to not stall the pipeline what more do you want” kind of attitude.
Go look at anything post-2000: 64 bit means that pointers take up 64 bits. 32 bits means that pointers take up 32 bits. 8-bit and 16-bit are completely relegated to microcontrollers, I think keeping the data bus terminology, and soonish they’re going to be gone because everything at that scale will be RISC-V, where “RV32I” means… pointers. So does “RV64I” and “RV128I”. RV16E was proposed as an April Fool’s joke and it’s not completely out of the question that it’ll happen. In any case there won’t be RV8 because CPUs with an 8-bit address bus are pointlessly small, and “the number refers to pointer width” is the terminology of <currentyear>. An RV16 CPU might have a 16 bit data bus, it might have an 8 bit data bus, heck it might have a 256bit data bus because it’s actually a DSP and has vector instructions. Sounds like a rare beast but not entirely nonsensical.
Doesn’t mean it’s any less important, it’s just not a good marketing measure,because average people wouldn’t understand it anyway, and it wouldn’t be correct to measure by the Databus alone.
As I stated it’s MORE complex today, not less, as the downvoters of my posts seem to refuse to acknowledge. The first Pentium had a 64 bit Databus for a 32 bit CPU. Exactly because data transfer is extremely important. The first Arm CPU was designed around as fast RAM access/management as possible, and it beat the 386 by several factors, with a tenth the transistors.
Although true, this is a very simplistic way to view it, and not relevant to the actual overall bitwith of the CPU, as I’ve tried to demonstrate, but people apparently refuse to acknowledge.
But bit width of the Databus is very important, and it was debated heavily weather it was even legal to market the M68008 Sinclair QL as a 32 bit computer, because it only had an 8 bit databus.
But as I stated other factors are equally important, and the decoder is way more important than the core instruction set, and modern higher end decoders operate at 256 bit or more, allowing them to decode multiple ( 4 ) instructions per cycle, again allowing each core to execute multiple instructions per clock, in 2 threads. Without that capability, each core would only be about a third as fast.
To claim that the instruction set determines bit wdth is simplistic, and also you yourself argued against it, because that would mean an i486 would be an 80 bit CPU. And obviously todays CPU’s would be 512 bit, because they have 512 bit instructions.
Calling it 64 bit is exclusively meant to distinguish newer CPU’s from older 32 bit CPUS, and we’ve done that since the 90’s, claiming that new CPU architectures haven’t increased in bit width for 30 years is simply naive and false, because they have in many more significant ways than the base instruction set.
Still I acknowledge that an AARCH64 or AMD64 or i64 CPU are generally called 64 bit, it was never the point to refute that. Only that it’s a gross simplification of what modern CPU’s have become, and that it’s not technically correct.
Let me finish with a question:
With a multi-core CPU where each core is let’s just say 64 bit, how many bits is the whole CPU package? Which is what we call the “CPU” today, when saying CPU we are not generally talking about the individual cores, because then it would have to be plural.
The reason you’re getting downvoted is because you’re saying that “64-bit CPU” means something different than is universally acknowledged that it means. It means pointer width.
Yes, other numbers are important. Yes, other numbers can be listed in places. No, it’s not what people mean when they say “X-bit CPU”.
RV128 exists. It refers to pointer width. Crays existed, by your account they were gazillion-bit machines because they had quite chunky vector lengths. Your Ryzen does not have a larger “databus” than a Cray1 which had 4096 bit (you read that right) vector registers. They were never called 4096 bit machines, they Cray1 has a 64-bit architecture because that’s the pointer width.
Yes, the terminology differs when it comes to 8 vs. 16-bit microcontrollers. But just because data bus is that important there (and 8-bit pointers don’t make any practical sense) doesn’t mean that anyone is calling a Cray a 4096 bit architecture. You might call them 4096 bit vector machines, and you’re free to call anything with AVX2 a 256-bit SIMD machine (though you might actually be looking at 2x 128-bit ALUs), but neither makes them 64-bit architectures. Why? Because language is meant for communication and you don’t get to have your own private definition of terms: Unless otherwise specified, the number stated is the number of bits in a pointer.
https://en.wikipedia.org/wiki/64-bit_computing
It also states Address bus, but as I mentioned before, that doesn’t exist. So it boils down to instruction set as a whole requiring 64 bit processor registers and Databus.
Obviously 64 bits means registers are 64 bit, the addresses are therefore also 64 bit, otherwise it would require type casting every time you need to make calculations on them. But it’s the ability to handle 64 bit registers in general that counts, not the address registers. which is merely a byproduct.
You were arguing the definition of “X-bit CPU”. We’re not talking about “X-bit ALU”. It’s also not up to contention that “A 64-bit integer is 64 bit wide”. So, to the statement:
This does not say which of “processor register, address buses, or data buses” applies to CPU and which to ALU.
Having 64 bit registers doesn’t necessitate that you have 64 bit addresses. It’s common, incredibly common, for the integer registers to match the pointer width but there’s no hard requirement in theory or practice. It’s about as arbitrary a rule as “Instruction length must be wider than the register size”, so that immediate constants fit into the instruction stream, makes sense doesn’t it… and then along come RISC architectures and split load immediate instructions into two.
Processors don’t typecast. Please stop talking.
Which is why it’s such a pain, because you have to do it manually:
https://lemire.me/blog/2021/10/21/converting-binary-floating-point-numbers-to-integers/
I’m sorry are we somehow assuming floating-point pointers, now, of course you need to convert there. “casting” is a specific thing you do in C which may or may not involve conversion of actual data. Processors don’t speak C. Processors don’t have a type system.
You can use 32-bit pointers in x86_64 long mode, no issue. You don’t even need to bit-fiddle:
mov rax, [esi]is perfectly legal. Opcode0x67488B06. Dereferencingrsiwould be0x488B06.“floating-point pointers” is not a thing:
No it’s not:
https://en.wikipedia.org/wiki/Type_conversion
You don’t even have a clue, you are just talking trash.
In assembly you don’t generally talk about pointers, but address modes. Like register, immediate or memory (indirect).
Have you ever actually been programming any serious assembly? Because you sure don’t sound like it.
deleted by creator
Where did you get that from? Because that’s false, please show me dokumentation for that.
64 bit always meant the ability to handle 64 bit wide instructions, and because the architecture is 64 bit, the pointers INTERNALLY are 64 bit, but effectively they are only for instance 40 bit when accessing data.
Your claim about pointer width simply doesn’t make any sense.
That the CPU should be called by a single aspect they can’t actually handle!!! That’s moronic.
People literally use the word “literally” to mean figuratively. It doesn’t make any sense. One might even call it moronic.
But it’s the way it’s done. Deal with it.